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exponent303
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Mathematic Formula For Drug Concentration-ANDY PLEASE CHECK THIS OUT!!!
Ok guys i wondered why should we always calculate the amount of a steroid inside our body (after an initial amount injected)
only in segments of halflifes?And if the steroid has a halflife of
7 days and we inject every two days how do we calculate then?
Before we go on:By steroid halflife we mean the time required for
a specific drug to be reduced at a quantity half the initial.
The math concept is simple:lets take a drug with a halflife of 7 days for example(nandrolone decanoate if you prefer)
The first day you inject Ymg:
DAY 1 ------ Ymg {every 7 days the drug amount gets half}
DAY 2 ------ ?
DAY 3 ------ ?
DAY 4 ------ ?
...
DAY 8 -------Y/2mg
DAY 9 -------?
DAY 10 -----?
DAY 11 -----?
...
DAY 15 -----(Y/2)/2=Y/4mg
...
DAY 22 -----(Y/4)/2=Y/8mg
...
DAY 29 -----(Y/8)/2=Y/16mg
...
and so on.
NOW LETS PLAY WITH THE NUMBERS!!!
DAY1 = DAY{1+0x7} and Y:=Y/2*0 or Y
DAY8 = DAY{1+1x7} and Y:=Y/2*1 or Y/2
DAY15=DAY{1+2x7} and Y:=Y/2*2 or Y/4
DAY22=DAY{1+3x7} and Y:=Y/2*3 or Y/8
DAY29=DAY{1+4x7} and Y:=Y/2*4 or Y/16
DAY36=DAY{1+5x7} and Y:=Y/2*5 or Y/32
...
After a closer look at the numbers above we notice that a
mathematical relation exists between the days and the subdivisions of the initial drug amount Y:
This relation can be expressed as :
DAY{1+Nx7} and Y:=Y/2*N which describes the above completely.(above: N=1,2,3,... )
So we have days 1,15,22,29,36,43,... and the corresponding amounts of drug fr these BUT WE DONT KNOW ABOUT THE DAYS BETWEEN THOSE ...
We'll do a mathematic trick:
lets say : 1+Nx7=M , then N=(M-1)/7 , so we can say instead:
DAY{M} and Y:=Y/2*[(M-1)/7]. M=1,2,3,...
Then: DAY{1} you'll have Y mg.
DAY{2} you'll have Y/2*(1/7) mg
DAY{3) you'll have Y/2*(2/7) mg
DAY{4} you'll have Y/2*(3/7) mg
...
DAY{8} you'll have Y/2*(7/7)=Y/2mg
and so on.
If you like mathematic equations here it is:
AMOUNT(day)=(AMOUNTinitial)/2*[(day-1)/7]
(day:1,2,3,4,5,...)
AMOUNT(day):the amount of drug at the beginning of day 1,2,3,4,...
AMOUNTinitial:first injection in mgs.
If you want an EXPLANATION on how the above formula can work look:
The equation says:
AMOUNT(day)=(AMOUNTinitial)/2*[(day-1)/7]
(The part (day-1)/7 is the EXPONENT of the number 2 not
a multiplication sign or something else.)
Also AMOUNT(1) is defined as the amount of drug in your body
RIGHT AFTER you have injected.Thus AMOUNT(8) is the amount of substance in your body 7 days after day one and that means
at the beginning of day 8.If you study this theory carefully you will notice that the time periods 1-8 , 8-15 , 15-22 , 22-29 ,...
are exactly 7 days. Considering the above lets see the concentration till day 8
initial amount=Y , halflife=7)
DAY(1): Y/{2*(0/7)}=Y/{2*0)=Y/1=Y (we know that 2*0=1)
DAY(2): Y/{2*(1/7)}=Y/{2*0.14285}=Y/1.10409=0.9057 Y
DAY(3): Y/{2*(2/7)}=Y/{2*0.28571}=Y/1.21901=0.8203 Y
DAY(4): Y/{2*(3/7)}=Y/{2*0.42857}=Y/1.3459 =0.7429 Y
DAY(5): Y/{2*(4/7)}=Y/{2*0.57142}=Y/1.48599=0.6729 Y
DAY(6): Y/{2*(5/7)}=Y/{2*0.71428}=Y/1.64067=0.6095 Y
DAY(7): Y/{2*(6/7)}=Y/{2*0.85714}=Y/1.81144=0.5520 Y
DAY(8): Y/{2*(7/7)}=Y/{2*1}=Y/2=0.5 Y
and so on for the following days...
I think this explanation solves many problems.This theory calculates the drug amount in your body AFTER ONE SINGLE SHOT.Considering for example that you shoot in time periods of (lets say) 3 days you calculate what is left in your body at the end of the 3rd day and then you add it to the next amount you shoot.You REUSE this formula again and again until you shoot the last ampoule.
I KNOW SOME GUYS WILL SAY ITS USELESS MATHEMATIC BULLSHIT but with this theory you have flexibility of calculating drug amounts even when shooting at non-regular time periods.
The same way as before we can show that for any drug halflife:
AMOUNT(day)=(AMOUNTinitial)/2*[(day-1)/HALFLIFE]
HALFLIFE:is a number for example 7 days.
What do you think guys?
I want your opinions.The same proof can be done even for seconds or millisecs!!!!!!!!
I WANT FEEDBACK-AND PLEEEEASE DONT TELL ME THAT I FOUND IT SOMEWHERE ELSE COS I CAN READJUST IT FOR EVERY TIME UNIT U CAN IMAGINE TO PROVE ITS ORIGINALITY..........
Ok guys i wondered why should we always calculate the amount of a steroid inside our body (after an initial amount injected)
only in segments of halflifes?And if the steroid has a halflife of
7 days and we inject every two days how do we calculate then?
Before we go on:By steroid halflife we mean the time required for
a specific drug to be reduced at a quantity half the initial.
The math concept is simple:lets take a drug with a halflife of 7 days for example(nandrolone decanoate if you prefer)
The first day you inject Ymg:
DAY 1 ------ Ymg {every 7 days the drug amount gets half}
DAY 2 ------ ?
DAY 3 ------ ?
DAY 4 ------ ?
...
DAY 8 -------Y/2mg
DAY 9 -------?
DAY 10 -----?
DAY 11 -----?
...
DAY 15 -----(Y/2)/2=Y/4mg
...
DAY 22 -----(Y/4)/2=Y/8mg
...
DAY 29 -----(Y/8)/2=Y/16mg
...
and so on.
NOW LETS PLAY WITH THE NUMBERS!!!
DAY1 = DAY{1+0x7} and Y:=Y/2*0 or Y
DAY8 = DAY{1+1x7} and Y:=Y/2*1 or Y/2
DAY15=DAY{1+2x7} and Y:=Y/2*2 or Y/4
DAY22=DAY{1+3x7} and Y:=Y/2*3 or Y/8
DAY29=DAY{1+4x7} and Y:=Y/2*4 or Y/16
DAY36=DAY{1+5x7} and Y:=Y/2*5 or Y/32
...
After a closer look at the numbers above we notice that a
mathematical relation exists between the days and the subdivisions of the initial drug amount Y:
This relation can be expressed as :
DAY{1+Nx7} and Y:=Y/2*N which describes the above completely.(above: N=1,2,3,... )
So we have days 1,15,22,29,36,43,... and the corresponding amounts of drug fr these BUT WE DONT KNOW ABOUT THE DAYS BETWEEN THOSE ...
We'll do a mathematic trick:
lets say : 1+Nx7=M , then N=(M-1)/7 , so we can say instead:
DAY{M} and Y:=Y/2*[(M-1)/7]. M=1,2,3,...
Then: DAY{1} you'll have Y mg.
DAY{2} you'll have Y/2*(1/7) mg
DAY{3) you'll have Y/2*(2/7) mg
DAY{4} you'll have Y/2*(3/7) mg
...
DAY{8} you'll have Y/2*(7/7)=Y/2mg
and so on.
If you like mathematic equations here it is:
AMOUNT(day)=(AMOUNTinitial)/2*[(day-1)/7]
(day:1,2,3,4,5,...)
AMOUNT(day):the amount of drug at the beginning of day 1,2,3,4,...
AMOUNTinitial:first injection in mgs.
If you want an EXPLANATION on how the above formula can work look:
The equation says:
AMOUNT(day)=(AMOUNTinitial)/2*[(day-1)/7]
(The part (day-1)/7 is the EXPONENT of the number 2 not
a multiplication sign or something else.)
Also AMOUNT(1) is defined as the amount of drug in your body
RIGHT AFTER you have injected.Thus AMOUNT(8) is the amount of substance in your body 7 days after day one and that means
at the beginning of day 8.If you study this theory carefully you will notice that the time periods 1-8 , 8-15 , 15-22 , 22-29 ,...
are exactly 7 days. Considering the above lets see the concentration till day 8
initial amount=Y , halflife=7) DAY(1): Y/{2*(0/7)}=Y/{2*0)=Y/1=Y (we know that 2*0=1)
DAY(2): Y/{2*(1/7)}=Y/{2*0.14285}=Y/1.10409=0.9057 Y
DAY(3): Y/{2*(2/7)}=Y/{2*0.28571}=Y/1.21901=0.8203 Y
DAY(4): Y/{2*(3/7)}=Y/{2*0.42857}=Y/1.3459 =0.7429 Y
DAY(5): Y/{2*(4/7)}=Y/{2*0.57142}=Y/1.48599=0.6729 Y
DAY(6): Y/{2*(5/7)}=Y/{2*0.71428}=Y/1.64067=0.6095 Y
DAY(7): Y/{2*(6/7)}=Y/{2*0.85714}=Y/1.81144=0.5520 Y
DAY(8): Y/{2*(7/7)}=Y/{2*1}=Y/2=0.5 Y
and so on for the following days...
I think this explanation solves many problems.This theory calculates the drug amount in your body AFTER ONE SINGLE SHOT.Considering for example that you shoot in time periods of (lets say) 3 days you calculate what is left in your body at the end of the 3rd day and then you add it to the next amount you shoot.You REUSE this formula again and again until you shoot the last ampoule.
I KNOW SOME GUYS WILL SAY ITS USELESS MATHEMATIC BULLSHIT but with this theory you have flexibility of calculating drug amounts even when shooting at non-regular time periods.
The same way as before we can show that for any drug halflife:
AMOUNT(day)=(AMOUNTinitial)/2*[(day-1)/HALFLIFE]
HALFLIFE:is a number for example 7 days.
What do you think guys?
I want your opinions.The same proof can be done even for seconds or millisecs!!!!!!!!
I WANT FEEDBACK-AND PLEEEEASE DONT TELL ME THAT I FOUND IT SOMEWHERE ELSE COS I CAN READJUST IT FOR EVERY TIME UNIT U CAN IMAGINE TO PROVE ITS ORIGINALITY..........
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