RoidCalc updated

[Dillett]

Andy14, I can't see your GIF picture, cause I dont have any Platinum membership, can you send it to me ? ([email protected])

I'm using the correct algorithm: CurrentValue=CurrentInject+(PreviousInject*Exp(-(LN2/halflife)*TimeSinceLast)), of course everything is not realeased directly. But I think I will implement your 'Active calculation' also, thanks for the tip.


Tren suggestions,

If Trenebolone have 2 days of half-life then you will have the same values as Test. Propionate, so use the Virormone/TestoVis/TestoPin column for Tren, you can also change the half-life for Boldenon to 2 days, and then use that for Tren calculations, it's quite easy.

 

[Hugh Gellatts]

much karma. this calc correllates alot better with actual active amount...cool

 

[Andy13]

Andy14, I can't see your GIF picture, cause I dont have any Platinum membership, can you send it to me ? ([email protected])

I'm using the correct algorithm: CurrentValue=CurrentInject+(PreviousInject*Exp(-(LN2/halflife)*TimeSinceLast)), of course everything is not realeased directly. But I think I will implement your 'Active calculation' also, thanks for the tip.


Tren suggestions,

If Trenebolone have 2 days of half-life then you will have the same values as Test. Propionate, so use the Virormone/TestoVis/TestoPin column for Tren, you can also change the half-life for Boldenon to 2 days, and then use that for Tren calculations, it's quite easy.

Here's how I derived the one I use..


[1] dy/dx =-kx the rate is proportional to the starting amount

Integrating both sides ....[2] lny = KX +C

[3] y=e^(KX) + e^C [e^c is a constant, so this becomes...]

[4] y=Ce^(kx)

we know that when y=C, (amount injected=amount injected) x (day) must be zero.

We also know that when y=1/2, x=h (half life day #)
Solving for K....

k= ln(1/2)/h

Putting this back into equation [4], we have

[5] y=C*e^(ln(1/2)*x/h)


I think I used n for x and k for c, but you get the picture. You would then program the series:
(sigma)[C*e^(ln(1/2)*x/h) - C*e^(ln(1/2)*(x+1)/h)]

For a sum for each day.

Andy

 

[ironmaster]

Whatever with the dang math...........I'ts so refreshing to see a post that is aimed at helping and advising, instead of the usual drivel.
You obviously put a lot of thought and work into this, I think it's real close to my personal experiences with these drugs. And the calc is very usable. Bound to help many plan their cycles better. Good job!

 

[Dillett]

Thank you all Muscleheadz , the main idea with this RoidCalc is to show how important it is with proper frontloading AND when to inject to keep the bloodvalue at a stable level. A good cycle should show some effects within 1-2 weeks, not 4-5 weeks as some people believe.

Andy, I think that the algoritm that I'm using will render the same results as yours. I have a new function called 'View active' where you can see how much is released from the esters, as you suggested.

/Dille

PS. Andy, check out the 'thanks' section and please verify that my Active calculation is ok. Don't forget that I have a -5% waste included.

 

[Andy13]

Andy, I think that the algoritm that I'm using will render the same results as yours. I have a new function called 'View active' where you can see how much is released from the esters, as you suggested.

Your (basic) equation is the same as mine. Before, I put my injection amounts in the wrong place on your chart.. Your roidcalc looks good.

PS. Andy, check out the 'thanks' section and please verify that my Active calculation is ok. Don't forget that I have a -5% waste included.

lol.. I was just joking about the credits section

Also, where did you read that 5% is lost? Did Bill Roberts tell you that or did you get if from one of your references.

 

[Themachine01]

very cool

 

[Hustler_dt]

nice job with that

 

[SUST-MAN]

GREAT JOB BRO!
THIS SHOULD BE A STICKY!

 

[centy]

bump. Any of you guys have much experience with the calc?