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I love catching CSI being wrong. Samoth get in here.

Scotsman

New member
Grissom said that terminal velocity is 9.8M/s^2 but that's just the expression for the acceleration due to the force of gravity on Earth. Sometimes I think they purposely throw in some wrong info so us science geeks can feel empowered.

Cheers,
Scotsman
 
I believe terminal velocity is around 198mph. I didn't google or anything so I could be wrong. Standard freefall is around 120mph.
 
Beachbum1546 said:
I believe terminal velocity is around 198mph. I didn't google or anything so I could be wrong. Standard freefall is around 120mph.

It's dependent on the object and weather condition taking into account drag. Although in a vacuum all objects fall at the same rate.

Cheers,
Scotsman
 
Scotsman said:
It's dependent on the object and weather condition taking into account drag. Although in a vacuum all objects fall at the same rate.

Cheers,
Scotsman
Yeah, and marshmallows get real huge too. :qt:
 
Scotsman if I wanted to learn about Newtons law and other things associated with Science as you just spoke about where should I look?


Thanx!
 
that is terminal velocity, not actual velocity, it is a maximum dependent not on drag but the terminal amount of force applied to the object. Terminal velocity is a constant be it a feather or a bb
 
BrothaBill said:
that is terminal velocity, not actual velocity, it is a maximum dependent not on drag but the terminal amount of force applied to the object. Terminal velocity is a constant be it a feather or a bb


lol, you're an idiot.
 
we will define the y-axis as being normal everywhere to the surface of the earth (taking into account the spherical shape of the earth, not its topographical features). Positive direction away from the center of the earth.

Terminal velocity will happen when the drag force perfectly balances the objects mass x acceleration due to gravity.

Usually a drag force is dependent on the square of the velocity multiplied some coefficient k. (k is usually based on the physical features of the body being observed, usually it is determined experimentally)

So we can say that the sum of the forces in the y direction are equal to zero at this instance.

SUM(F) = kV^2 - ma = 0.

Solving for terminal V: V = [ma/k]^1/2
 
juicedmohawk said:
lol, you're an idiot.

Look its the speed at which atmospheric drag matches the pull of gravity, resulting in a constant fall rate; a body falling at maximum acceleration. But, actual terminal velocity can only be done in a vacuum idiot, free of drag, meaning that terminal velocity does indeed equal the rate of gravitational acceleration which 9.8 meters per second per second, duh
 
Did ya kn ow Peanut butter & Jelly Sanwiches vanish just as fast as cupcakes?
(RADAR's Law)




RADAR
 
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