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Brain teaser....

  • Thread starter Thread starter The Shadow
  • Start date Start date
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The Shadow

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k to first correct answer.


Complete the next 2 numbers in the sequence:

2, 12, 360, 75,600 ........
 
edit... you said two numbers and I don't have a calculator
 
Late to the party but I dispute the answer anyway. I know you can Google for the answers above.

2, 12, 360, 75600

142884000, 2970558360000


Take the original number and multiply it by 3 to give 6 for use as a multiplier.

Multiply the previous multiplier by the last bump number + 2.

6 * 5 -> 30
30 * 7 -> 210
210 * 9 -> 1890
1890 * 11 -> 20790

75600 * 1890 = 142884000
142884000 * 20790 = 2970558360000
 
blut wump said:
Late to the party but I dispute the answer anyway. I know you can Google for the answers above.

2, 12, 360, 75600

142884000, 2970558360000


Take the original number and multiply it by 3 to give 6 for use as a multiplier.

Multiply the previous multiplier by the last bump number + 2.

6 * 5 -> 30
30 * 7 -> 210
210 * 9 -> 1890
1890 * 11 -> 20790

75600 * 1890 = 142884000
142884000 * 20790 = 2970558360000

i know you won't believe me but I did it this way first. I really do think either answer is correct, which is common for these type of problems.
 
I believe you. The original problem should have specified an extra term. The underlying numbers often provoke unexpected sequences, especially when powers are invlolved and we have two mods here.
 
blut wump said:
I believe you. The original problem should have specified an extra term. The underlying numbers often provoke unexpected sequences, especially when powers are invlolved and we have two mods here.

The only reason why I didn't post the answer your way was because my calculator only shows 4 or 5 digits (some cheap ass thing), so i had to do it by hand and I refigured the problem.
 
hamstershaver said:
you are <cough> very <bullshit> smart for doing that in your <google> head

do you need a cough drop?
or some tylenol? you seem to have a cough and your fever is making you delerious.
 
stilleto said:
do you need a cough drop?
or some tylenol? you seem to have a cough and your fever is making you delerious.

you have admitted to googling answers to k threads before yknow lol
I can picture you all studious with pen and paper, biting on your tongue out the side of your mouth with an old fashioned accounting machine with the crank, checking the printout, doublechecking with an abacus, but I think you are more of a point A to point B person with google lol
 
BrothaBill said:
you have admitted to googling answers to k threads before yknow lol
I can picture you all studious with pen and paper, biting on your tongue out the side of your mouth with an old fashioned accounting machine with the crank, checking the printout, doublechecking with an abacus, but I think you are more of a point A to point B person with google lol

of course I have googled answers- it didn't dawn on me to google a math problem though. it wasn't difficult to figure out- just time consuming to get the answer- it was all division and multiplication.
I have a page of scribbled numbers to prove it. :)
 
I just took another look at my solution against the powers one. They are, of course, the same solution except that the powers one is more clearly based on primes rather than simple odd numbers. By basing mine on odd numbers I was led to a factor of 9 after 7 rather than a leap to 11. If I press on to mutiplying by 11 then 13 rather than by 9 and then 11 I get the same answers as everyone else, which is to be expected.

I think they are each valid solutions since the author didn't allow sufficient of the sequence to show to demand that primes be used, although you could argue the converse by indicating that the sequence begins with a 2.

There's no need to Google for this for anyone accustomed to ferreting out sequences.
 
blut wump said:
I just took another look at my solution against the powers one. They are, of course, the same solution except that the powers one is more clearly based on primes rather than simple odd numbers. By basing mine on odd numbers I was led to a factor of 9 after 7 rather than a leap to 11. If I press on to mutiplying by 11 then 13 rather than by 9 and then 11 I get the same answers as everyone else, which is to be expected.

I think they are each valid solutions since the author didn't allow sufficient of the sequence to show to demand that primes be used, although you could argue the converse by indicating that the sequence begins with a 2.

There's no need to Google for this for anyone accustomed to ferreting out sequences.

I did 7,9,11 first when I used a calculator (if anyone had been watching, my first reply to this thread was posting your answers, except i could only go around 4 numbers past the decimal and that wasn't working well so i edited it), but when I did it by hand I thought that logically, adding 2 to the sequence seemed less likely than just using primes- based on the first number of the series.
but, that was pretty much a logical guess, either answer is right.

even though i posted mine first. :)
 
I have to think that only my answer is the correct one by virtue of encompassing both answers and a family of others with different start values.
 
While I must congratulate your celerity, I think mine encompasses all plausible answers.

Oh, I just noticed that he's already paid out. Congrats.
 
blut wump said:
While I must congratulate your celerity, I think mine encompasses all plausible answers.

Oh, I just noticed that he's already paid out. Congrats.

I shared a bit of the wealth with you. :)
although, your answer only encompasses half of the plausible answers, and your methodology only covered half of the process.

i do, however, think we can both agree to the fact that hamstershaver wasn't even friggin' close. ;)
 
blut wump said:
I just took another look at my solution against the powers one. They are, of course, the same solution except that the powers one is more clearly based on primes rather than simple odd numbers. By basing mine on odd numbers I was led to a factor of 9 after 7 rather than a leap to 11. If I press on to mutiplying by 11 then 13 rather than by 9 and then 11 I get the same answers as everyone else, which is to be expected.

I think they are each valid solutions since the author didn't allow sufficient of the sequence to show to demand that primes be used, although you could argue the converse by indicating that the sequence begins with a 2.

There's no need to Google for this for anyone accustomed to ferreting out sequences.

K to you as well as you are correct
 
blut wump said:
Thanks, Shadow, most generous.

I have to think that Hammy was deprived on a technicality.

I don't see this....tell me how.

He only gave ONE of the numbers.

Had he given BOTH as was specified, he would have been the winner for one of the correct answers.
 
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