Samoth, help me figure out this Fluid Statics problem

[UA_Iron]

This was one of my test questions today:

In the question it should say the rod is 4m long and the cross sectional area is 40cm^2. The picture is correct.

 

[75th]

The answer is pi squared I think.

 

[75th]

*Disclaimer: I have no clue what the fuck that is.

 

[Tiervexx]

This was one of my test questions today:

In the question it should say the rod is 4m long and the cross sectional area is 40cm^2. The picture is correct.

I won't be studing that stuff until next year, otherwise I'd gladly help.

 

[juiceddreadlocks]

Does this problem have anything to do with the strength of the Yen?

 

[75th]

Does this problem have anything to do with the strength of the Yen?

Retard, it's the Euro.

 

[BrothaBill]

This was one of my test questions today:

In the question it should say the rod is 4m long and the cross sectional area is 40cm^2. The picture is correct.

cmon man think it through, whats the specific weight of water, the object is 20% above that times its mass. Convert that to anti-newtons to give you the buoyancy factor. Look in the book youre studying to get the equation to convert the rod as an offset given its angle and then calculate the angle of theta. If I had a physics books itd be as simple as pi to calculate it for you. Its just a plug and chug equation to solve. Calculate the force upwards or the buoyancy factor. Find the equation that involves the rod and angulation, should be in a physics book, done lots of problems like that. Then calculate theta, prolly have to calculate the length of the rod in the water using pythagoreans theorem with the 50 cm out of the water giving the lenth out of water, subtract that from the length of the rod to give you the lengh in the water, calculate its buoyancy and add that to the buoyancy of the block . essentially you have two objects that float. The block and the portion of the arm that lies in the water. As they rise, the portion of the arm will be a function of the buoyancy as it lifts portions of the swingarm out of the water subtracting that from the two objects combined buoyancy. Has to be a simple equation for this problem to plug and chug

 

[samoth]

I've never studied statics directly, nor fluid statics/dynamics, but it looks like just throwing a bunch of long, annoying mechanics eqns together and spending 2 hours converting all the damned units would be the basic plan of attack. I'd totally rather be doing that than studying for a latin exam. I love how it gives you the density of water, lol.

I've leafed through a couple fluid dynamics texts before... those look ungodly fucking brutal.

 

[samoth]

BTW Jeff, you ever use Fowles & Cassiday's 'Analytical Mechanics' text for anything? Or Griffith's E&M or Intro QM texts?

... just curious, as I could totally hook you up with some shit if you did...

 

[-SD-]

Pick the answer marked "True".....damn this is easy.

 

[UA_Iron]

No samoth I dont use those books, but I do have almost complete solutions for a lot of the books that I am using right now.

There's someway to break the buoyancy force up into what acts on the block and the rod then using moments about C and set those equal to zero because the problem is static.

What messes up the problem is that the rod is partially submerged but there's gotta be an easy way around it. I dont think finding buoyancy force as a function of area submerged is the way to do it...it would just get complicated as the effective area the buoyancy acts over is also dependent on the angle...

 

[samoth]

Can't you just make like a mathematician and throw some approximations and assumptions around? Like, start the answer out as, "assume a fully submerged rod isomorphic to the identical but partially submerged rod in the diagram to be of negligable difference to the definded system and parameters" and go from there.

Would you get partial credit if you just showed that an answer exists, thereby reducing it to a previously solved problem, and leave it at that? LOL, I've always wanted to do a joke like that or something on an exam.

 

[Becoming]

stop doing homework on the meathead boards....

 

[UA_Iron]

stop doing homework on the meathead boards....

that was the other option...punching the TA in the neck and forcing him into giving me an A.

I asked the TA about that assumption the other day Samoth, he said to break it up into two parts.

 

[samoth]

that was the other option...punching the TA in the neck and forcing him into giving me an A.

I asked the TA about that assumption the other day Samoth, he said to break it up into two parts.

LOL, I was kidding about the apprx...

There's a lot of worthless TA's out there, you're more than encouraged to cause him great bodily harm. He will pay for the incompetency of his race.

 

[Lestat]

fuckin samote is all over this thing like white on rice

 

[Testosterone boy]

Whats the specific weight of water, the object is 20% above that times its mass. Convert that to anti-newtons to give you the buoyancy factor. Look in the book youre studying to get the equation to convert the rod as an offset given its angle and then calculate the angle of theta. If I had a physics books itd be as simple as pi to calculate it for you. Its just a plug and chug equation to solve. Calculate the force upwards or the buoyancy factor. Find the equation that involves the rod and angulation, should be in a physics book, done lots of problems like that. Then calculate theta, prolly have to calculate the length of the rod in the water using pythagoreans theorem with the 50 cm out of the water giving the lenth out of water, subtract that from the length of the rod to give you the lengh in the water, calculate its buoyancy and add that to the buoyancy of the block . essentially you have two objects that float. The block and the portion of the arm that lies in the water. As they rise, the portion of the arm will be a function of the buoyancy as it lifts portions of the swingarm out of the water subtracting that from the two objects combined buoyancy.

 

[samoth]

Damn, another BB alter I didn't know about. That's over 40 now, not even including myself.

 

[biteme]

I use to be real smart. Made an A in statistics, algebra, and trig. I forgot all of that stuff. Never used it. Except for maybe statistics a few times.