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need physics help

Sub-Zero

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A 500 g model rocket is on a cart that is rolling to the right at a speed of 3.0 m/s. The rocket engine, when it is fired, exerts an 8.0 N thrust on the rocket. Your goal is to have the rocket pass through a small horizontal hoop that is 20 m above the launch point.

At what horizontal distance left of the loop should you launch?
 
does the rocket fire straight up? If so, I think I might be about to figure it out. Just remember independent X/Y directions.
 
SublimeZM said:
A 500 g model rocket is on a cart that is rolling to the right at a speed of 3.0 m/s. The rocket engine, when it is fired, exerts an 8.0 N thrust on the rocket. Your goal is to have the rocket pass through a small horizontal hoop that is 20 m above the launch point.

At what horizontal distance left of the loop should you launch?

assuming that the rocket keeps moving to the right at 3.0 m/s after launch you first calculate the time it takes for the rocket to travel 20m.

Acceleration is F = MA, 0.5 KG for mass, and Force is 8 N so A is 16 m/s.

So functions for movement are:

a(t) = 16
v(t) = 16t
p(t) = 8t^2

Solve for p(t) = 20

t = 1.58 seconds.

Next question is how far will the cart move to the right in 1.58 seconds?

Answer is 1.58*3 = 4.74 meters.

I realize this might be too late but I wanted to see if I could remember how to do this stuff because I have not seen such problems in years.
 
funny_cat_pictures_30.jpg
 
Tiervexx said:
assuming that the rocket keeps moving to the right at 3.0 m/s after launch you first calculate the time it takes for the rocket to travel 20m.

Acceleration is F = MA, 0.5 KG for mass, and Force is 8 N so A is 16 m/s.

So functions for movement are:

a(t) = 16
v(t) = 16t
p(t) = 8t^2

Solve for p(t) = 20

t = 1.58 seconds.

Next question is how far will the cart move to the right in 1.58 seconds?

Answer is 1.58*3 = 4.74 meters.

I realize this might be too late but I wanted to see if I could remember how to do this stuff because I have not seen such problems in years.

you forgot to subtract the accel due to gravity from the accel of the thrust, ohhhhhhhhh
 
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