chaos mage said:
pound isn't a unit of force, for starters. 2nd, this is retarded. 3rd, he would be pressing 891N sin (30°)
Not quite, far more complicated.
200 lbs = 0.454Kg = 90.8Kg * gravity(9.8/m per second squared) = 889.84 Newtons of Force downwards at the initial point of him just about to start the push up.
You then separate the triangle into vertical and horizontal components.
Triangle has a height of 3 feet, and a hypotenuse of 6 feet, so the base is:
Root of(36 - 9) = 5
Making one angle 90 degrees, the farthest one 33.56 degrees and the man-arm one ( 90 - 33.56 ) = 56.44 degrees
Using components, at initial vector start-up, his y-axis component would be:
889.84(Force downwards) - (Force deflected by his position)889.4cos(56.44)
Force(initial) = 889.4N - 491.7N = 397.7N Resultant Force down
Thats the force necessary to maintain his current position.
When he does the push up, all angles become zero, and F = 397.7 Newtons expended.
THEN, when he pushes up again, the Force is the same but negative(But we have to take the absolute value)
Therefore, total Net resultant force done by the man for one push up is 795.4 Newtons.
The x-axis is in the horizontal direction and is ignored always in these cases.
As the derrivative of any horizontal line = 0.