Please Scroll Down to See Forums Below lol, troll, you make me laugh. 
You Math Smart? Problem -- Two Guns
- Thread starter THeMaCHinE
- Start date
fistfullofsteel
Well-known member
it does make a difference because the more it travels the more velocity it loses and the more gravity pulls it to the ground. i saw a show with snipers taking shots from a quater mile away, and they said that must take gravity into account. there would be some sort of difference due to gravity but it will be insignificant most likely in this case unless you want to get in billionth's of a second
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good 
now say "i'm sorry troll, you are a better reader than me. i being a texaslonghorn didn't learn how to slow down and evaluate a problem before jumping toward a conclusion. i wasted money on an expensive education when all i had to do was find you, and let you show me the way
"
now say "i'm sorry troll, you are a better reader than me. i being a texaslonghorn didn't learn how to slow down and evaluate a problem before jumping toward a conclusion. i wasted money on an expensive education when all i had to do was find you, and let you show me the way
"
fistfullofsteel
Well-known member
Troll said:good
now say "i'm sorry troll, you are a better reader than me. i being a texaslonghorn didn't learn how to slow down and evaluate a problem before jumping toward a conclusion. i wasted money on an expensive education when all i had to do was find you, and let you show me the way
i am not sorry for anything, and i don't want a part of your education either. you can keep it to yourself. if you got an education to educate me, then you should ask for a refund. i said there would be a difference, and i am happy that you agreed.
I hate to break this to you troll, but I got the correct answer. I did misread the part about the muzzle length/distance from head.
Lol, you must not be used to reading to be so happy about that part, and also so distraught about it at the same time.
So, to answer yellowd's question, the answer is the gun that is closer to the head. The punchline is troll.
Lol, you must not be used to reading to be so happy about that part, and also so distraught about it at the same time.
So, to answer yellowd's question, the answer is the gun that is closer to the head. The punchline is troll.
fist,
bro. i'm just trying to help you understand the world you live in. the bullet will not slow down due to gravity. i'm sorry, that's just the way it is.
V = Vo + .5*a*t^2
V is velocity.
Vo is the initial velocity.
a is acceleration
t is time
there are three components of velocity in a cartesian coordiante system. If we lable our axis X, Y and Z, there will be Vx, Vy, and Vz components of the velocity.
for this problem we let the positive X axis point toward the EAST, the Z axis points SOUTH, and the Y axis points straight up.
Now Gravity is 32ft/s/s in the negative Y direction.
This means ax=0, ay=-32/ft/s/s, and az=0.
so,
Vx = Vox + .5*ax*t^2
Vy = Voy + .5*ay*t^2
Vz = Voz + .5*az*t^2
plugging in our understanding of gravity we find that low and behold.
Vx = Vox
Vy = Voy +.5*-32*t^2
Vz = Voz
The components in the x and z directions are unaffected by gravity.
your thinking to pratical, of course the bullet will hit the ground eventually, due to the decrease in the Vy, but this problem doesn't address that portion of the motion.
*note: if you look at the equation for Vy you can see that time will always grow, so eventually the second part of that sum will become dominate, and will change the direction of motion.
bro. i'm just trying to help you understand the world you live in. the bullet will not slow down due to gravity. i'm sorry, that's just the way it is.
V = Vo + .5*a*t^2
V is velocity.
Vo is the initial velocity.
a is acceleration
t is time
there are three components of velocity in a cartesian coordiante system. If we lable our axis X, Y and Z, there will be Vx, Vy, and Vz components of the velocity.
for this problem we let the positive X axis point toward the EAST, the Z axis points SOUTH, and the Y axis points straight up.
Now Gravity is 32ft/s/s in the negative Y direction.
This means ax=0, ay=-32/ft/s/s, and az=0.
so,
Vx = Vox + .5*ax*t^2
Vy = Voy + .5*ay*t^2
Vz = Voz + .5*az*t^2
plugging in our understanding of gravity we find that low and behold.
Vx = Vox
Vy = Voy +.5*-32*t^2
Vz = Voz
The components in the x and z directions are unaffected by gravity.
your thinking to pratical, of course the bullet will hit the ground eventually, due to the decrease in the Vy, but this problem doesn't address that portion of the motion.
*note: if you look at the equation for Vy you can see that time will always grow, so eventually the second part of that sum will become dominate, and will change the direction of motion.
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fistfullofsteel
Well-known member
the more the bullet loses velocity the more gravity has chance of taking over? is that not true?
