some calculus help

[Burnboy]

solve this:

(2/3((square root of x)^3+ (suqare root of delta x)^3)+2/3(square root of x)^3)/deltax

im trying to find ia drivative, the original problem was 2/3(x)^(3/2)

 

[Stanknogger]

You can't "solve" that as it is not an equation.

I aint gonna do your homework for you, but the derivative of any monomimal a*x^n with respect to x, is:

d(a*x^n)/dx = n*a*x^(n-1)

there go figure it out

 

[chesty]

no way, that is simple. and he is not trying to solve an equation, just find the derivitive of it. Big difference.

 

[KING]

first derivative or second derivative?

first would just be

multiply constant by exponent and subtract exponent by one,

example-


3x (exponent 4) = 12x (exponent 3) that is first derivative


36x (exponet 2) is the second derivative.

Do not make thing more complicated than what they really are.




Your awnser is this -


2/3x^3/2

fisrt derivative is 2/3 * 3/2 is = 1x^1/2 or x^1/2


the formula that I use is -

n(x)^p derivative - n(p)x^p-1

 

[Fonz]

solve this:

(2/3((square root of x)^3+ (suqare root of delta x)^3)+2/3(square root of x)^3)/deltax

im trying to find ia drivative, the original problem was 2/3(x)^(3/2)

I have no clue as to what deltaX stands for, but here is the solution
including no substitution for deltaX:
(English math differs from american math)


3 * (deltaX)^2 + (X)exp(0.5) + (X)exp(0.5)deltaX

So,

3 * (deltaX)^2 + (deltaX * (X)exp(0.5)) + ((X)exp(0.5))

3deltaX^2 + deltaX(X)exp(0.5) + (X)exp(0.5)

deltaX [ 3deltaX + (X)exp(0.5) + (X)exp(0.5)

deltaX [ 3deltaX + 2Xexp(0.5) ]

And there it is.

So, deltaX = 0 or 3deltaX= - 2Xexp(0.5)
deltaX= - 2/3(X)exp(0.5)



Godspeed

 

[Iceman121]

Damn I wish I hadn't opened this post...........Makes me feel like an idiot.
I have no clue what in the hell you are talking about......