KillahBee said:You just had to give that pic it's own thread, didn't you?

LMAO, I just noticed the tampering.redguru said:By the way the answer is bulb #1.
![]()
blut wump said:LMAO, I just noticed the tampering.
blut wump said:Talking of currents, I remember a joke from school.
The local shopkeeper's daughter was notorious for not wearing any underwear. One day little Timmy went to the store and ordered a quarter pound of currents and raisins. Not so little Suzie had to climb the ladder to reach the jar giving Timmy the grand vista of the gates of heaven.
"Is it raisin", she enquired as she stretched for the jar.
"It sure is" said Timmy, "and it's throbbing too".
jack_schitt said:dude...I'm reading the schematic thinking this was a serious electrical theory question, and then I saw the KillaBee thing....
Good Lord, I havent laughed that hard in days LMFAO!!
You aint rite man...you just aint fuggin rite lololololllol
redguru said:By the way the answer is bulb #1.
![]()
swole said:Redguru beat me to it.
The answer is definitely bulb #1.
Resistors in parallel have the same voltage, therefore making lightbulbs #2 and 3 the same brightness.
When you put resistors in series (bulb #1 is in series with #2), they both have the same current, but not as much voltage. You can think of bulb #2 and 3 as one lightbulb. The 2nd bulb will be dimmer than the first and would shine as bright as bulb #3...therefore making bulb #1 the brightest.
this is so freshman year stuff
i giggled quietly to myself after seeing killah's name in it
I did the same thing...jack_schitt said:dude...I'm reading the schematic thinking this was a serious electrical theory question, and then I saw the KillaBee thing....
Good Lord, I havent laughed that hard in days LMFAO!!
You aint rite man...you just aint fuggin rite lololololllol
This page contains mature content. By continuing, you confirm you are over 18 and agree to our TOS and User Agreement.
Please Scroll Down to See Forums Below 










