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Another riddle

  • Thread starter Thread starter The Shadow
  • Start date Start date
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The Shadow

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...man is in a boat holding a bowling ball.

He pitches the ball over into the lake.

How does the water level change after dumping the ball??


Does it:


Raise

Lower

Stay the same
 
stays the same..its a fucking lake, the measurement of water displacement is too minute to even consider.

plus it will splash some water back into the boat

plus you do NOT bowl on Sabath Shabbus (sp?)

So SHUT THE FUCK UP DONNY (osmond)

heh
 
stays same displacement was already accounted for by being in the boat/weighing it down and causing it to displace more water.
 
Hamster is on the right track...but the choice doesnt matter
 
oh yeah.....you need to state why answered the way that you did
 
fuck it, i dont like bowling..the only thing about bowling i like is that movie Big Lebowski
 
Bowling Balls
by the shadow

So round and smooth
I love my balls
I roll them around
'till they bounce off the walls

I usually play alone
but sometimes I want more
its lonely being me
but I can't seem to score. :(
 
Once while swimming cross turtle creek Man them snappers right at my feet
Sure was hard swimming cross that thing with both hands holding my dingaling

My Ding-A-Ling My Ding-A-Ling won't you play with My Ding-A-Ling
 
if the density of the bowling ball is greater than that of the water then the water level of the lake will decrease (ever so slightly). The bowling ball is displacing the amount of water equal to its weight which is more than the balls volume.

But this is a "riddle" so something fishy is up.
 
The Shadow said:
...man is in a boat holding a bowling ball.

He pitches the ball over into the lake.

How does the water level change after dumping the ball??


Does it:


Raise

Lower

Stay the same


the riddle states he pitches a ball over it does not say he pitches the bowling ball over the bowling ball there for can not change anything about the lake...he could have thrown a beach ball in that would be floating
 
I guess it would depend on what the ball is made out of...Does its weight force it to float? sink, bob up and down....force has the opposite force...so depends what the bowling ball is putting out unno..........I would think anyways....
 
UA_Iron said:
if the density of the bowling ball is greater than that of water

Better go check your engineering manual to find out if the density of a bowling ball is greater than that of water :lmao: :lmao: :lmao:

Damn engineers, lol.



:cow:
 
samoth said:
Better go check your engineering manual to find out if the density of a bowling ball is greater than that of water :lmao: :lmao: :lmao:

Damn engineers, lol.



:cow:

settle down, it was first thing in the morning - but yeah you're right that water is more dense.
 
UA_Iron said:
settle down, it was first thing in the morning - but yeah you're right that water is more dense.

Settle down, it was an engineering jo*

Wait, what?!?

I don't know if you're serious or messing with my head, lol. What are bowling balls make of? I just realized that I have no idea, lol. Your answer was correct, though.

And I know our time zones aren't that different... 3:15pm is first thing in the morning? You're either still on break or have a kick-ass schedule this semester, lol.



:cow:
 
Shadow go fuck your sister Marie Osmond..

cant PM a brother back?

kak
 
samoth said:
Settle down, it was an engineering jo*

Wait, what?!?

I don't know if your serious or messing with my head, lol. What are bowling balls make of? I just realized that I have no idea, lol. Your answer was correct, though.

And I know our time zones aren't that different... 3:15pm is first thing in the morning? You're either still on break or have a kick-ass schedule this semester, lol.



:cow:

had class at 10am, was up at 8:00

anyway - what's the average volume of a bowling ball? We'll backwards solve this problem.
 
UA_Iron said:
had class at 10am, was up at 8:00

anyway - what's the average volume of a bowling ball? We'll backwards solve this problem.

I've gone bowling maybe five times in my life, lol. I just know that they're really heavy balls. And that I really, really suck at bowling.

Your first post got it right with the volume and water displacement and stuff. I was just trying to make an engineering joke. ;)



:cow:
 
samoth said:
I've gone bowling maybe five times in my life, lol. I just know that they're really heavy balls. And that I really, really suck at bowling.

Your first post got it right with the volume and water displacement and stuff. I was just trying to make an engineering joke. ;)



:cow:

come on physics major....


I'll save the calculations but an equivalent sized volume of water would be 18.7lbs for a diameter of 10" and 32.62lbs for a 12" diameter

bowling balls range from 8-16lbs

density of water is greater
 
UA_Iron said:
come on physics major....


I'll save the calculations but an equivalent sized volume of water would be 18.7lbs for a diameter of 10" and 32.62lbs for a 12" diameter

bowling balls range from 8-16lbs

density of water is greater

LOL, really? I seriously didn't know that. I usually look up the density or whatever of something on ChemFinder, but I don't even know what bowling balls really are.

My friends always do some funny hand-tuck throw with the light pink balls to get it to curve... I'm still working on knocking pins down on every turn, lol.

PWN3D by engineering :(



:cow:
 
Pervis Ellison said:
Shadow go fuck your sister Marie Osmond..

cant PM a brother back?

kak

if I had a pm I would.....check your sent messages cuz I didnt get shit


it comes down to weight versus volume on the brain teaser.

Does the ball displace more water due to its weight in the boat, or its volume??

You pitch it and the level goes down - its WEIGHT displaces more water than its volume.

So when you pitch it, the water level DROPS as less volume is displaced

Bowling Balls
by the shadow

So round and smooth
I love my balls
I roll them around
'till they bounce off the walls

I usually play alone
but sometimes I want more
its lonely being me
but I can't seem to score.
 
Last edited by a moderator:
If water were denser than a bowling ball, the ball would float. Those numbers are wrong.
 
I still say you cant answer it with the info provided ..the riddle did not say he pitched in the bowling ball ...just a ball
 
digger said:
If water were denser than a bowling ball, the ball would float. Those numbers are wrong.

haha, I think you may be onto something digger.

My calculations were off - but an 8lb bowling ball will float in water while a 16lb one would sink.


nsta01bowl6.jpg


owned by digger :(
 
Stays the same, doesn't matter if the ball is in the boat or in the lake; the same weight/volume is being applied whether through the boat with all things on board, or if the ball is thrown in the lake. It's a matter of displacement.
 
hanselthecaretaker said:
Stays the same, doesn't matter if the ball is in the boat or in the lake; the same weight/volume is being applied whether through the boat with all things on board, or if the ball is thrown in the lake. It's a matter of displacement.

Given a 16lb ball...

not true - if the bowling ball's density is greater than that of water then:

Initially the weight of the water displaced will be equal to the weight of the bowling ball. After throwing the ball into the water the volume of the water displaced will be equal to the volume of the bowling ball. Now, provided that the ball sinks, it would be clear that ball weighs more per unit volume than the water - aka it has a greater density.

So essentially the initial 16lbs of water displaced will weigh more than water displaced equal to the volume of the bowling ball.

I dont know why I am having trouble explaining this...weird.
 
UA_Iron said:
haha, I think you may be onto something digger.

My calculations were off - but an 8lb bowling ball will float in water while a 16lb one would sink.


nsta01bowl6.jpg


owned by digger :(
are those 2 bowling balls made out of the same material in that pic?
i know that there are 3 different types of material that a bb is made out of:
plastic
resin
urethane
would not what the ball is made out of affect if it floats or sinks?
 
hamstershaver said:
are those 2 bowling balls made out of the same material in that pic?
i know that there are 3 different types of material that a bb is made out of:
plastic
resin
urethane
would not what the ball is made out of affect if it floats or sinks?

yes - they are composed of a couple different compounds actually - so the net effect of the different compounds its made out of.
 
hamstershaver said:
are those 2 bowling balls made out of the same material in that pic?
i know that there are 3 different types of material that a bb is made out of:
plastic
resin
urethane
would not what the ball is made out of affect if it floats or sinks?

Not really, if the bowling balls are all standard sized (27" Circumference), A 12lb resin ball would have the same mass per unit volume as a 12lb urethane ball. The question to ask Shadow, since he didn't give us enough information, is did the ball sink or float?
 
redguru said:
Not really, if the bowling balls are all standard sized (27" Circumference), A 12lb resin ball would have the same mass per unit volume as a 12lb urethane ball. The question to ask Shadow, since he didn't give us enough information, is did the ball sink or float?
it doenst matter that a resin ball would be more porous than a plastic ball?
 
hamstershaver said:
it doenst matter that a resin ball would be more porous than a plastic ball?

Not really, because they have to increase the mass of the core of the ball to make it weigh as much as a similar plastic ball. Unsure of what differing core shapes would do to the math. Knowing that cores are offset drilled for varying degrees of hook. So a 8lb Urethane Ball will float as will an 8lb Plastic ball. Both balls will sink at around 12lb.
 
The real question to ponder is: was the boat in the lake or next to it???????????? EH? EHHHHHHHHHHHHHHHHHHHHHHHH? EHH? Whatever I hate physics.
 
Here's the deal,Density= M/V so if the bowling ball has a density of greater than one (assuming the intent of the question, also note that the density of water equals one, thats how they set it up, 100g per 100mL or 100/100= 1) then it will sink and lower the water. For sake of the argument lets say that the bowling ball has a density of 1.5 or 150g per 100mL volume. In fact for ease will just say the ball IS 150g and 100mL to illustrate (or 300g and 200 mL and so on as long as the ratio is 1.5). You can plug and chug any numbers later based on your favorite bowling ball specifications. *note: using the metric system would make it much easier so first thing is to convert bowling ball specs to grams and mL.

In the boat the bowling ball caused the water to rise by an amount equal to the weight of the bowling ball. 150g (displaceing 150mL water)
Once thrown over, the water is displaced by the volume of the bowling ball (not the weight). 100 mL (which displaces obviously 100mL water)
Its weight is heavier than water, the weight displaces more water than its volume and the water level thus would go down. That is if its mass divided by volume is greater than 1.

Why is that, because, 150g/100mL in water (100mg/100mL)
So in the boat weight the bowling ball weight of 150g displaces that much water (density of water 100g/100mL) so 150g would displace 150mL of water if displacement was done by weight.
Once dropped in, instead of displacement by weight it switches to displacement by volume, for the example explanation we set the ball at 150g/100mL so the displacement once in the water would be 100mL.

Weight displacement=150mL
Volume displacement=100mL
Hence, if dropped in, an object with a density greater than one would displace less by volume than mass. B/c D=M/V whereas M is less than V, the D < 1 and floats, M is greater than V, D > 1 and sinks.

Now would the inverse be true if the density of the object was less than one? Meaning it would float.
Would it increase the water level given what I just said or would it stay the same?

What if instead of a bowling ball it was a ball of clay with a density greater than one and before you throw it over board you form the clay into the shape of a boat?


to make it easy, anything dropped from a boat and sinks would lower the water level
 
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Bill is correct.

Any standard bowling ball will sink....hence lowering the water level as I said before.


It all comes down to mass versus the volume in space that the mass occupies.
 
The Shadow said:
Bill is correct.

Any standard bowling ball will sink....hence lowering the water level as I said before.


It all comes down to mass versus the volume in space that the mass occupies.

there's standard 8lb bowling balls that will float. :)

But if the ball sinks the water level will lower after throwing it in.

Redguru is right, there's not enough info.
 
UA_Iron said:
there's standard 8lb bowling balls that will float. :)

But if the ball sinks the water level will lower after throwing it in.

Redguru is right, there's not enough info.

So what will happen to the water level if the bowling ball floats after being tossed from a boat?
Will it go up or stay the same?
 
UA_Iron said:
there's standard 8lb bowling balls that will float. :)

But if the ball sinks the water level will lower after throwing it in.

Redguru is right, there's not enough info.



Are you accounting for the finger holes being filled with water when you account for the density??
 
BrothaBill said:
So what will happen to the water level if the bowling ball floats after being tossed from a boat?
Will it go up or stay the same?
LMAO....


Dont throw a curve yet
 
The Shadow said:
Are you accounting for the finger holes being filled with water when you account for the density??

well yeah you should, but on each toss there's a good chance that not all the finger holes will be filled with water...

BrothaBill said:
So what will happen to the water level if the bowling ball floats after being tossed from a boat?
Will it go up or stay the same?

I was thinking about that too....

I think it will go up as well - in the boat the water displaced will be equal to the weight of the bowling ball. While floating in the water the bowling ball will displace the volume of water equal to the submersed portion of the bowling ball.

we had a physics problem like this a few years back - I'll see if I can dig it up.
 
UA_Iron said:
well yeah you should, but on each toss there's a good chance that not all the finger holes will be filled with water...





we had a physics problem like this a few years back - I'll see if I can dig it up.
Dropping the ball would generate enough force to completely submerge it, yes??
 
UA_Iron said:
well yeah you should, but on each toss there's a good chance that not all the finger holes will be filled with water...



I was thinking about that too....

I think it will go up as well - in the boat the water displaced will be equal to the weight of the bowling ball. While floating in the water the bowling ball will displace the volume of water equal to the submersed portion of the bowling ball.

we had a physics problem like this a few years back - I'll see if I can dig it up.


Lets say that the bowling ball density was 75g per 100mL of bowling ball volume.
In the boat, its weight displaced 75mL of water correct, because water is 100g per 100mL.

We've established that it would float b/c its density is less than water.

So since it floats then its displacement is still based on weight not volume, ergo, the water level would stay the same.

In both instances, in the boat and floating itself, the weight, 75g displaces 75mL of water
 
The Shadow said:
Dropping the ball would generate enough force to completely submerge it, yes??

it would reach an appropriate velocity such that its momentum would overcome bouyant forces.

Ideally, we would analyze the state at its two equilibriums - the initial and final states. If the density were less than that of water it would come back up to the surface and float even after being launched into the water. So realistically a time scale must be defined - especially when dealing with the ball that floats.


BrothaBill said:
Lets say that the bowling ball density was 75g per 100mL of bowling ball volume.
In the boat, its weight displaced 75mL of water correct, because water is 100g per 100mL.

We've established that it would float b/c its density is less than water.

So since it floats then its displacement is still based on weight not volume, ergo, the water level would stay the same.

In both instances, in the boat and floating itself, the weight, 75g displaces 75mL of water

Let us look at a macro scale before we get into smaller unit scales. The 8lb ball on the boat will displace 8lbs of water - completely independent of the density.

While partially submerged the ball will displace the amount of water equal to that of the volume of the partially submerged portion of the ball. From here I believe that the 8lbs of water it displaces initially will weigh more than that of the volume of the water displaced by the partially submerged ball. It is still unclear to me at this point, I will give it some thought.
 
UA_Iron said:
it would reach an appropriate velocity such that its momentum would overcome bouyant forces.

Ideally, we would analyze the state at its two equilibriums - the initial and final states. If the density were less than that of water it would come back up to the surface and float even after being launched into the water. So realistically a time scale must be defined - especially when dealing with the ball that floats.




Let us look at a macro scale before we get into smaller unit scales. The 8lb ball on the boat will displace 8lbs of water - completely independent of the density.

While partially submerged the ball will displace the amount of water equal to that of the volume of the partially submerged portion of the ball. From here I believe that the 8lbs of water it displaces initially will weigh more than that of the volume of the water displaced by the partially submerged ball. It is still unclear to me at this point, I will give it some thought.


It doesnt matter if its in a boat or not, if it floats, the displacement is by weight not volume.
An eight pound bowling ball displaces eight pounds of water in a boat or just floating, in both cases, the density is less than one meaning mass is what determines its ability to displace water.
When density is over one, the displacement is based upon volume.
Under one, its by mass.

The mass of the ball is what forces its proportionate volume under the surface. The opposing force is the water and it reaches equilibrium based on mass.
In both instances, 8lbs is the mass and it will displace 8lbs of water. The amount of water 8lbs will displace can be calculated by the volume of the portion of the bowling ball that is submerged.

Same with the amount the boat is lowered in the water if someone were to place the ball into the floating boat. The boat would displace the same amount of water as the floating bowling ball.
Its Archimede's principle
 
what is the man doing with a bowling ball in a boat?
 
Erzulie said:
what is the man doing with a bowling ball in a boat?

Demonstrating that engineering students arent taught Archimede's principle
that a floating object will displace a volume of water that has a weight equal to the weight of the object that is floating. :lmao:
UA_Iron said:
From here I believe that the 8lbs of water it displaces initially will weigh more than that of the volume of the water displaced by the partially submerged ball.


cow.gif
 
Last edited:
BrothaBill said:
Demonstrating that engineering students arent taught Archimede's principle
that a floating object will displace a volume of water that has a weight equal to the weight of the object that is floating.


Isn't this supposed to be a riddle? Most riddles are typically "If johnny as 8 apples and gives Susie 5 how many do you have?" and not a lesson in upper level college physics. My guess, which could be horribly wrong, is that we all missed something pretty obvious and that shadow is just adding fuel to the fire with his encouragement of this physics voodoo.
 
BrothaBill said:
Demonstrating that engineering students arent taught Archimede's principle
that a floating object will displace a volume of water that has a weight equal to the weight of the object that is floating. :lmao:
cow.gif

;)
 
crew9 said:
Isn't this supposed to be a riddle? Most riddles are typically "If johnny as 8 apples and gives Susie 5 how many do you have?" and not a lesson in upper level college physics. My guess, which could be horribly wrong, is that we all missed something pretty obvious and that shadow is just adding fuel to the fire with his encouragement of this physics voodoo.

well it started out as a bowling ball and a boat, you can determine the answer with a see through bucket, a rock, a black marker and a butter tray and mark the water levels. But describing why that occurs its easier to talk in accepted principles.
To prove Im correct all one has to do is substitute the rock with a superball and measure the water levels to show that they wont change. Thats what Archimedes did a couple thousand years ago with similar instruments
Hence you could answer the riddle with digital photos


cow.gif
 
crew9 said:
Isn't this supposed to be a riddle? Most riddles are typically "If johnny as 8 apples and gives Susie 5 how many do you have?" and not a lesson in upper level college physics. My guess, which could be horribly wrong, is that we all missed something pretty obvious and that shadow is just adding fuel to the fire with his encouragement of this physics voodoo.

that would be 0
 
crew9 said:
Woah woah quit showing off here and get back to the problem at hand.

somethings got to give.. up down to the left or to the right.. that fugging water is gonna move
 
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